In the school hall, chairs were arranged in rows of 10. During a function, 34 chairs were added to accommodate the number of people. The chairs were rearranged to form rows of 8. As a result, there were 7 more rows.
- How many chairs were there in the extra 7 rows?
- How many chairs were there in the school hall in the end?
|
First arrangement |
Second arrangement |
Number |
1 u |
1 u + 7 |
Value |
10 |
8 |
Total value |
10 u |
8 u + 56 |
(a)
Number of chairs in the extra 7 rows
= 7 x 8
= 56
(b)
Total number of chairs in the first arrangement
= 1 u x 10
= 10 u
Total number of chairs in the second arrangement
= 8(1 u + 7)
= 8 u + 56
If 34 chairs were included in the first arrangement, the total number of chairs in the first arrangement and the second arrangement will be the same.
10 u + 34 = 8 u + 56
10 u - 8 u = 56 - 34
2 u = 22
1 u = 22 ÷ 2 = 11
Number of chairs in the school hall in the end
= 11 x 10 + 34
= 110 + 34
= 144
Answer(s): (a) 56; (b) 144