Rio, Joe and Jed had the same number of notes. Rio and Joe had a mix of $50-notes and $10-notes. Rio had 2 $50-notes while Joe had 11 $50-notes. Jed only had $50-notes.

1. Who had the least amount of money?
2. How much more did Joe have than Rio?
3. Joe used all his $10-notes to buy a wallet. He then had $1750 less than Jed. How many $50-notes did Jed have?

(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $10-notes.

Since Rio had the least number of $50-notes, he had the least money.

(b)
Number of more $50-notes that Joe had than Rio
= 11 - 2
= 9

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Amount that Joe had more than Rio
= 9 x 40
= $360

(c)
Value of $50-notes that Joe had left
= 11 x 50
= $550

Total value that Jed had
= 550 + 1750
= $2300

Number of $50-notes that Jed had
= 2300 ÷ 50
= 46

Answer(s): (a) Rio; (b) $360; (c) 46