Rey, Tom and Sam had the same number of notes. Rey and Tom had a mix of $50-notes and $10-notes. Rey had 10 $50-notes while Tom had 19 $50-notes. Sam only had $50-notes.
- Who had the least amount of money?
- How much more did Tom have than Rey?
- Tom used all his $10-notes to buy a wallet. He then had $1000 less than Sam. How many $50-notes did Sam have?
(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $10-notes.
Since Rey had the least number of $50-notes, he had the least money.
(b)
Number of more $50-notes that Tom had than Rey
= 19 - 10
= 9
Difference in the value of $50-note and $10-note
= 50 - 10
= $40
Amount that Tom had more than Rey
= 9 x 40
= $360
(c)
Value of $50-notes that Tom had left
= 19 x 50
= $950
Total value that Sam had
= 950 + 1000
= $1950
Number of $50-notes that Sam had
= 1950 ÷ 50
= 39
Answer(s): (a) Rey; (b) $360; (c) 39
