Lee, Tim and Dan had the same number of notes. Lee and Tim had a mix of $100-notes and $5-notes. Tim had 6 $100-notes while Lee had 11 $100-notes. Dan only had $100-notes.
- Who had the least amount of money?
- How much less did Tim have than Lee?
- Lee used all his $5-notes to buy a wallet. He then had $3500 less than Dan. How many $100-notes did Dan have?
(a)
The three boys had the same number of notes.
$100-notes have a higher denomination than $5-notes.
Since Tim had the least number of $100-notes, he had the least money.
(b)
Number of less $100-notes that Tim had than Lee
= 11 - 6
= 5
Difference in the value of $100-note and $5-note
= 100 - 5
= $95
Amount that Tim had less than Lee
= 5 x 95
= $475
(c)
Value of $100-notes that Lee had left
= 11 x 100
= $1100
Total value that Dan had
= 1100 + 3500
= $4600
Number of $100-notes that Dan had
= 4600 ÷ 100
= 46
Answer(s): (a) Tim; (b) $475; (c) 46
