Ace, Ari and Rio had the same number of notes. Ace and Ari had a mix of $100-notes and $10-notes. Ace had 10 $100-notes while Ari had 13 $100-notes. Rio only had $100-notes.

1. Who had the least amount of money?
2. How much more did Ari have than Ace?
3. Ari used all his $10-notes to buy a wallet. He then had $1800 less than Rio. How many $100-notes did Rio have?

(a)
The three boys had the same number of notes.
$100-notes have a higher denomination than $10-notes.

Since Ace had the least number of $100-notes, he had the least money.

(b)
Number of more $100-notes that Ari had than Ace
= 13 - 10
= 3

Difference in the value of $100-note and $10-note
= 100 - 10
= $90

Amount that Ari had more than Ace
= 3 x 90
= $270

(c)
Value of $100-notes that Ari had left
= 13 x 100
= $1300

Total value that Rio had
= 1300 + 1800
= $3100

Number of $100-notes that Rio had
= 3100 ÷ 100
= 31

Answer(s): (a) Ace; (b) $270; (c) 31