Roy, Zac and Dan had the same number of notes. Roy and Zac had a mix of $50-notes and $20-notes. Roy had 15 $50-notes while Zac had 18 $50-notes. Dan only had $50-notes.

1. Who had the least amount of money?
2. How much more did Zac have than Roy?
3. Zac used all his $20-notes to buy a wallet. He then had $750 less than Dan. How many $50-notes did Dan have?

(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $20-notes.

Since Roy had the least number of $50-notes, he had the least money.

(b)
Number of more $50-notes that Zac had than Roy
= 18 - 15
= 3

Difference in the value of $50-note and $20-note
= 50 - 20
= $30

Amount that Zac had more than Roy
= 3 x 30
= $90

(c)
Value of $50-notes that Zac had left
= 18 x 50
= $900

Total value that Dan had
= 900 + 750
= $1650

Number of $50-notes that Dan had
= 1650 ÷ 50
= 33

Answer(s): (a) Roy; (b) $90; (c) 33