Roy, Lon and Don had the same number of notes. Roy and Lon had a mix of $10-notes and $5-notes. Lon had 15 $10-notes while Roy had 20 $10-notes. Don only had $10-notes.
- Who had the least amount of money?
- How much less did Lon have than Roy?
- Roy used all his $5-notes to buy a wallet. He then had $130 less than Don. How many $10-notes did Don have?
(a)
The three boys had the same number of notes.
$10-notes have a higher denomination than $5-notes.
Since Lon had the least number of $10-notes, he had the least money.
(b)
Number of less $10-notes that Lon had than Roy
= 20 - 15
= 5
Difference in the value of $10-note and $5-note
= 10 - 5
= $5
Amount that Lon had less than Roy
= 5 x 5
= $25
(c)
Value of $10-notes that Roy had left
= 20 x 10
= $200
Total value that Don had
= 200 + 130
= $330
Number of $10-notes that Don had
= 330 ÷ 10
= 33
Answer(s): (a) Lon; (b) $25; (c) 33
