Rio, Joe and Bo had the same number of notes. Rio and Joe had a mix of $10-notes and $5-notes. Joe had 4 $10-notes while Rio had 12 $10-notes. Bo only had $10-notes.
- Who had the least amount of money?
- How much less did Joe have than Rio?
- Rio used all his $5-notes to buy a wallet. He then had $350 less than Bo. How many $10-notes did Bo have?
(a)
The three boys had the same number of notes.
$10-notes have a higher denomination than $5-notes.
Since Joe had the least number of $10-notes, he had the least money.
(b)
Number of less $10-notes that Joe had than Rio
= 12 - 4
= 8
Difference in the value of $10-note and $5-note
= 10 - 5
= $5
Amount that Joe had less than Rio
= 8 x 5
= $40
(c)
Value of $10-notes that Rio had left
= 12 x 10
= $120
Total value that Bo had
= 120 + 350
= $470
Number of $10-notes that Bo had
= 470 ÷ 10
= 47
Answer(s): (a) Joe; (b) $40; (c) 47
