Dan, Joe and Ace had the same number of notes. Dan and Joe had a mix of $10-notes and $5-notes. Joe had 10 $10-notes while Dan had 17 $10-notes. Ace only had $10-notes.
- Who had the least amount of money?
- How much less did Joe have than Dan?
- Dan used all his $5-notes to buy a wallet. He then had $260 less than Ace. How many $10-notes did Ace have?
(a)
The three boys had the same number of notes.
$10-notes have a higher denomination than $5-notes.
Since Joe had the least number of $10-notes, he had the least money.
(b)
Number of less $10-notes that Joe had than Dan
= 17 - 10
= 7
Difference in the value of $10-note and $5-note
= 10 - 5
= $5
Amount that Joe had less than Dan
= 7 x 5
= $35
(c)
Value of $10-notes that Dan had left
= 17 x 10
= $170
Total value that Ace had
= 170 + 260
= $430
Number of $10-notes that Ace had
= 430 ÷ 10
= 43
Answer(s): (a) Joe; (b) $35; (c) 43
