Abe, Asa and Luc had the same number of notes. Abe and Asa had a mix of $100-notes and $20-notes. Asa had 6 $100-notes while Abe had 14 $100-notes. Luc only had $100-notes.

1. Who had the least amount of money?
2. How much less did Asa have than Abe?
3. Abe used all his $20-notes to buy a wallet. He then had $2900 less than Luc. How many $100-notes did Luc have?

(a)
The three boys had the same number of notes.
$100-notes have a higher denomination than $20-notes.

Since Asa had the least number of $100-notes, he had the least money.

(b)
Number of less $100-notes that Asa had than Abe
= 14 - 6
= 8

Difference in the value of $100-note and $20-note
= 100 - 20
= $80

Amount that Asa had less than Abe
= 8 x 80
= $640

(c)
Value of $100-notes that Abe had left
= 14 x 100
= $1400

Total value that Luc had
= 1400 + 2900
= $4300

Number of $100-notes that Luc had
= 4300 ÷ 100
= 43

Answer(s): (a) Asa; (b) $640; (c) 43