Luc, Rey and Rio had the same number of notes. Luc and Rey had a mix of $50-notes and $10-notes. Luc had 13 $50-notes while Rey had 16 $50-notes. Rio only had $50-notes.

1. Who had the least amount of money?
2. How much more did Rey have than Luc?
3. Rey used all his $10-notes to buy a wallet. He then had $1650 less than Rio. How many $50-notes did Rio have?

(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $10-notes.

Since Luc had the least number of $50-notes, he had the least money.

(b)
Number of more $50-notes that Rey had than Luc
= 16 - 13
= 3

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Amount that Rey had more than Luc
= 3 x 40
= $120

(c)
Value of $50-notes that Rey had left
= 16 x 50
= $800

Total value that Rio had
= 800 + 1650
= $2450

Number of $50-notes that Rio had
= 2450 ÷ 50
= 49

Answer(s): (a) Luc; (b) $120; (c) 49