Ace, Jed and Rio had the same number of notes. Ace and Jed had a mix of $100-notes and $5-notes. Ace had 2 $100-notes while Jed had 10 $100-notes. Rio only had $100-notes.
- Who had the least amount of money?
- How much more did Jed have than Ace?
- Jed used all his $5-notes to buy a wallet. He then had $4000 less than Rio. How many $100-notes did Rio have?
(a)
The three boys had the same number of notes.
$100-notes have a higher denomination than $5-notes.
Since Ace had the least number of $100-notes, he had the least money.
(b)
Number of more $100-notes that Jed had than Ace
= 10 - 2
= 8
Difference in the value of $100-note and $5-note
= 100 - 5
= $95
Amount that Jed had more than Ace
= 8 x 95
= $760
(c)
Value of $100-notes that Jed had left
= 10 x 100
= $1000
Total value that Rio had
= 1000 + 4000
= $5000
Number of $100-notes that Rio had
= 5000 ÷ 100
= 50
Answer(s): (a) Ace; (b) $760; (c) 50
