Ace, Joe and Roy had the same number of notes. Ace and Joe had a mix of $20-notes and $5-notes. Ace had 8 $20-notes while Joe had 14 $20-notes. Roy only had $20-notes.

1. Who had the least amount of money?
2. How much more did Joe have than Ace?
3. Joe used all his $5-notes to buy a wallet. He then had $600 less than Roy. How many $20-notes did Roy have?

(a)
The three boys had the same number of notes.
$20-notes have a higher denomination than $5-notes.

Since Ace had the least number of $20-notes, he had the least money.

(b)
Number of more $20-notes that Joe had than Ace
= 14 - 8
= 6

Difference in the value of $20-note and $5-note
= 20 - 5
= $15

Amount that Joe had more than Ace
= 6 x 15
= $90

(c)
Value of $20-notes that Joe had left
= 14 x 20
= $280

Total value that Roy had
= 280 + 600
= $880

Number of $20-notes that Roy had
= 880 ÷ 20
= 44

Answer(s): (a) Ace; (b) $90; (c) 44