Ken, Ray and Asa had the same number of notes. Ken and Ray had a mix of $50-notes and $20-notes. Ray had 7 $50-notes while Ken had 12 $50-notes. Asa only had $50-notes.
- Who had the least amount of money?
- How much less did Ray have than Ken?
- Ken used all his $20-notes to buy a wallet. He then had $1550 less than Asa. How many $50-notes did Asa have?
(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $20-notes.
Since Ray had the least number of $50-notes, he had the least money.
(b)
Number of less $50-notes that Ray had than Ken
= 12 - 7
= 5
Difference in the value of $50-note and $20-note
= 50 - 20
= $30
Amount that Ray had less than Ken
= 5 x 30
= $150
(c)
Value of $50-notes that Ken had left
= 12 x 50
= $600
Total value that Asa had
= 600 + 1550
= $2150
Number of $50-notes that Asa had
= 2150 ÷ 50
= 43
Answer(s): (a) Ray; (b) $150; (c) 43
