Sam, Ray and Dan had the same number of notes. Sam and Ray had a mix of $50-notes and $10-notes. Ray had 15 $50-notes while Sam had 18 $50-notes. Dan only had $50-notes.

1. Who had the least amount of money?
2. How much less did Ray have than Sam?
3. Sam used all his $10-notes to buy a wallet. He then had $1500 less than Dan. How many $50-notes did Dan have?

(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $10-notes.

Since Ray had the least number of $50-notes, he had the least money.

(b)
Number of less $50-notes that Ray had than Sam
= 18 - 15
= 3

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Amount that Ray had less than Sam
= 3 x 40
= $120

(c)
Value of $50-notes that Sam had left
= 18 x 50
= $900

Total value that Dan had
= 900 + 1500
= $2400

Number of $50-notes that Dan had
= 2400 ÷ 50
= 48

Answer(s): (a) Ray; (b) $120; (c) 48