Dan, Lee and Hal had the same number of notes. Dan and Lee had a mix of $50-notes and $5-notes. Lee had 7 $50-notes while Dan had 12 $50-notes. Hal only had $50-notes.
- Who had the least amount of money?
- How much less did Lee have than Dan?
- Dan used all his $5-notes to buy a wallet. He then had $1550 less than Hal. How many $50-notes did Hal have?
(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $5-notes.
Since Lee had the least number of $50-notes, he had the least money.
(b)
Number of less $50-notes that Lee had than Dan
= 12 - 7
= 5
Difference in the value of $50-note and $5-note
= 50 - 5
= $45
Amount that Lee had less than Dan
= 5 x 45
= $225
(c)
Value of $50-notes that Dan had left
= 12 x 50
= $600
Total value that Hal had
= 600 + 1550
= $2150
Number of $50-notes that Hal had
= 2150 ÷ 50
= 43
Answer(s): (a) Lee; (b) $225; (c) 43
