Bo, Rey and Lee had the same number of notes. Bo and Rey had a mix of $50-notes and $20-notes. Bo had 9 $50-notes while Rey had 14 $50-notes. Lee only had $50-notes.
- Who had the least amount of money?
- How much more did Rey have than Bo?
- Rey used all his $20-notes to buy a wallet. He then had $1550 less than Lee. How many $50-notes did Lee have?
(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $20-notes.
Since Bo had the least number of $50-notes, he had the least money.
(b)
Number of more $50-notes that Rey had than Bo
= 14 - 9
= 5
Difference in the value of $50-note and $20-note
= 50 - 20
= $30
Amount that Rey had more than Bo
= 5 x 30
= $150
(c)
Value of $50-notes that Rey had left
= 14 x 50
= $700
Total value that Lee had
= 700 + 1550
= $2250
Number of $50-notes that Lee had
= 2250 ÷ 50
= 45
Answer(s): (a) Bo; (b) $150; (c) 45
