Ray, Eli and Ari had the same number of notes. Ray and Eli had a mix of $50-notes and $20-notes. Eli had 9 $50-notes while Ray had 12 $50-notes. Ari only had $50-notes.

1. Who had the least amount of money?
2. How much less did Eli have than Ray?
3. Ray used all his $20-notes to buy a wallet. He then had $1150 less than Ari. How many $50-notes did Ari have?

(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $20-notes.

Since Eli had the least number of $50-notes, he had the least money.

(b)
Number of less $50-notes that Eli had than Ray
= 12 - 9
= 3

Difference in the value of $50-note and $20-note
= 50 - 20
= $30

Amount that Eli had less than Ray
= 3 x 30
= $90

(c)
Value of $50-notes that Ray had left
= 12 x 50
= $600

Total value that Ari had
= 600 + 1150
= $1750

Number of $50-notes that Ari had
= 1750 ÷ 50
= 35

Answer(s): (a) Eli; (b) $90; (c) 35