Ken, Asa and Bo had the same number of notes. Ken and Asa had a mix of $20-notes and $5-notes. Ken had 12 $20-notes while Asa had 15 $20-notes. Bo only had $20-notes.

1. Who had the least amount of money?
2. How much more did Asa have than Ken?
3. Asa used all his $5-notes to buy a wallet. He then had $380 less than Bo. How many $20-notes did Bo have?

(a)
The three boys had the same number of notes.
$20-notes have a higher denomination than $5-notes.

Since Ken had the least number of $20-notes, he had the least money.

(b)
Number of more $20-notes that Asa had than Ken
= 15 - 12
= 3

Difference in the value of $20-note and $5-note
= 20 - 5
= $15

Amount that Asa had more than Ken
= 3 x 15
= $45

(c)
Value of $20-notes that Asa had left
= 15 x 20
= $300

Total value that Bo had
= 300 + 380
= $680

Number of $20-notes that Bo had
= 680 ÷ 20
= 34

Answer(s): (a) Ken; (b) $45; (c) 34