Tom, Tim and Hal had the same number of notes. Tom and Tim had a mix of $20-notes and $10-notes. Tim had 8 $20-notes while Tom had 13 $20-notes. Hal only had $20-notes.

1. Who had the least amount of money?
2. How much less did Tim have than Tom?
3. Tom used all his $10-notes to buy a wallet. He then had $500 less than Hal. How many $20-notes did Hal have?

(a)
The three boys had the same number of notes.
$20-notes have a higher denomination than $10-notes.

Since Tim had the least number of $20-notes, he had the least money.

(b)
Number of less $20-notes that Tim had than Tom
= 13 - 8
= 5

Difference in the value of $20-note and $10-note
= 20 - 10
= $10

Amount that Tim had less than Tom
= 5 x 10
= $50

(c)
Value of $20-notes that Tom had left
= 13 x 20
= $260

Total value that Hal had
= 260 + 500
= $760

Number of $20-notes that Hal had
= 760 ÷ 20
= 38

Answer(s): (a) Tim; (b) $50; (c) 38