Rio, Dan and Roy had the same number of notes. Rio and Dan had a mix of $50-notes and $10-notes. Dan had 15 $50-notes while Rio had 18 $50-notes. Roy only had $50-notes.
- Who had the least amount of money?
- How much less did Dan have than Rio?
- Rio used all his $10-notes to buy a wallet. He then had $1200 less than Roy. How many $50-notes did Roy have?
(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $10-notes.
Since Dan had the least number of $50-notes, he had the least money.
(b)
Number of less $50-notes that Dan had than Rio
= 18 - 15
= 3
Difference in the value of $50-note and $10-note
= 50 - 10
= $40
Amount that Dan had less than Rio
= 3 x 40
= $120
(c)
Value of $50-notes that Rio had left
= 18 x 50
= $900
Total value that Roy had
= 900 + 1200
= $2100
Number of $50-notes that Roy had
= 2100 ÷ 50
= 42
Answer(s): (a) Dan; (b) $120; (c) 42