Ken, Ned and Abe had the same number of notes. Ken and Ned had a mix of $100-notes and $5-notes. Ken had 8 $100-notes while Ned had 13 $100-notes. Abe only had $100-notes.
- Who had the least amount of money?
- How much more did Ned have than Ken?
- Ned used all his $5-notes to buy a wallet. He then had $1900 less than Abe. How many $100-notes did Abe have?
(a)
The three boys had the same number of notes.
$100-notes have a higher denomination than $5-notes.
Since Ken had the least number of $100-notes, he had the least money.
(b)
Number of more $100-notes that Ned had than Ken
= 13 - 8
= 5
Difference in the value of $100-note and $5-note
= 100 - 5
= $95
Amount that Ned had more than Ken
= 5 x 95
= $475
(c)
Value of $100-notes that Ned had left
= 13 x 100
= $1300
Total value that Abe had
= 1300 + 1900
= $3200
Number of $100-notes that Abe had
= 3200 ÷ 100
= 32
Answer(s): (a) Ken; (b) $475; (c) 32
