Bo, Ray and Jim had the same number of notes. Bo and Ray had a mix of $100-notes and $5-notes. Bo had 6 $100-notes while Ray had 16 $100-notes. Jim only had $100-notes.
- Who had the least amount of money?
- How much more did Ray have than Bo?
- Ray used all his $5-notes to buy a wallet. He then had $2400 less than Jim. How many $100-notes did Jim have?
(a)
The three boys had the same number of notes.
$100-notes have a higher denomination than $5-notes.
Since Bo had the least number of $100-notes, he had the least money.
(b)
Number of more $100-notes that Ray had than Bo
= 16 - 6
= 10
Difference in the value of $100-note and $5-note
= 100 - 5
= $95
Amount that Ray had more than Bo
= 10 x 95
= $950
(c)
Value of $100-notes that Ray had left
= 16 x 100
= $1600
Total value that Jim had
= 1600 + 2400
= $4000
Number of $100-notes that Jim had
= 4000 ÷ 100
= 40
Answer(s): (a) Bo; (b) $950; (c) 40
