Dan, Jed and Ken had the same number of notes. Dan and Jed had a mix of $20-notes and $5-notes. Jed had 3 $20-notes while Dan had 13 $20-notes. Ken only had $20-notes.

1. Who had the least amount of money?
2. How much less did Jed have than Dan?
3. Dan used all his $5-notes to buy a wallet. He then had $500 less than Ken. How many $20-notes did Ken have?

(a)
The three boys had the same number of notes.
$20-notes have a higher denomination than $5-notes.

Since Jed had the least number of $20-notes, he had the least money.

(b)
Number of less $20-notes that Jed had than Dan
= 13 - 3
= 10

Difference in the value of $20-note and $5-note
= 20 - 5
= $15

Amount that Jed had less than Dan
= 10 x 15
= $150

(c)
Value of $20-notes that Dan had left
= 13 x 20
= $260

Total value that Ken had
= 260 + 500
= $760

Number of $20-notes that Ken had
= 760 ÷ 20
= 38

Answer(s): (a) Jed; (b) $150; (c) 38