Tom, Tim and Abe had the same number of notes. Tom and Tim had a mix of $100-notes and $20-notes. Tom had 1 $100-notes while Tim had 10 $100-notes. Abe only had $100-notes.
- Who had the least amount of money?
- How much more did Tim have than Tom?
- Tim used all his $20-notes to buy a wallet. He then had $3500 less than Abe. How many $100-notes did Abe have?
(a)
The three boys had the same number of notes.
$100-notes have a higher denomination than $20-notes.
Since Tom had the least number of $100-notes, he had the least money.
(b)
Number of more $100-notes that Tim had than Tom
= 10 - 1
= 9
Difference in the value of $100-note and $20-note
= 100 - 20
= $80
Amount that Tim had more than Tom
= 9 x 80
= $720
(c)
Value of $100-notes that Tim had left
= 10 x 100
= $1000
Total value that Abe had
= 1000 + 3500
= $4500
Number of $100-notes that Abe had
= 4500 ÷ 100
= 45
Answer(s): (a) Tom; (b) $720; (c) 45
