Jim, Sam and Lee had the same number of notes. Jim and Sam had a mix of $50-notes and $10-notes. Sam had 4 $50-notes while Jim had 14 $50-notes. Lee only had $50-notes.

1. Who had the least amount of money?
2. How much less did Sam have than Jim?
3. Jim used all his $10-notes to buy a wallet. He then had $1100 less than Lee. How many $50-notes did Lee have?

(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $10-notes.

Since Sam had the least number of $50-notes, he had the least money.

(b)
Number of less $50-notes that Sam had than Jim
= 14 - 4
= 10

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Amount that Sam had less than Jim
= 10 x 40
= $400

(c)
Value of $50-notes that Jim had left
= 14 x 50
= $700

Total value that Lee had
= 700 + 1100
= $1800

Number of $50-notes that Lee had
= 1800 ÷ 50
= 36

Answer(s): (a) Sam; (b) $400; (c) 36