Ace, Eli and Roy had the same number of notes. Ace and Eli had a mix of $20-notes and $10-notes. Ace had 5 $20-notes while Eli had 15 $20-notes. Roy only had $20-notes.

1. Who had the least amount of money?
2. How much more did Eli have than Ace?
3. Eli used all his $10-notes to buy a wallet. He then had $300 less than Roy. How many $20-notes did Roy have?

(a)
The three boys had the same number of notes.
$20-notes have a higher denomination than $10-notes.

Since Ace had the least number of $20-notes, he had the least money.

(b)
Number of more $20-notes that Eli had than Ace
= 15 - 5
= 10

Difference in the value of $20-note and $10-note
= 20 - 10
= $10

Amount that Eli had more than Ace
= 10 x 10
= $100

(c)
Value of $20-notes that Eli had left
= 15 x 20
= $300

Total value that Roy had
= 300 + 300
= $600

Number of $20-notes that Roy had
= 600 ÷ 20
= 30

Answer(s): (a) Ace; (b) $100; (c) 30