Don, Tim and Bo had the same number of notes. Don and Tim had a mix of $50-notes and $10-notes. Don had 10 $50-notes while Tim had 17 $50-notes. Bo only had $50-notes.
- Who had the least amount of money?
- How much more did Tim have than Don?
- Tim used all his $10-notes to buy a wallet. He then had $1000 less than Bo. How many $50-notes did Bo have?
(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $10-notes.
Since Don had the least number of $50-notes, he had the least money.
(b)
Number of more $50-notes that Tim had than Don
= 17 - 10
= 7
Difference in the value of $50-note and $10-note
= 50 - 10
= $40
Amount that Tim had more than Don
= 7 x 40
= $280
(c)
Value of $50-notes that Tim had left
= 17 x 50
= $850
Total value that Bo had
= 850 + 1000
= $1850
Number of $50-notes that Bo had
= 1850 ÷ 50
= 37
Answer(s): (a) Don; (b) $280; (c) 37
