Ty, Rey and Ace had the same number of notes. Ty and Rey had a mix of $20-notes and $5-notes. Rey had 9 $20-notes while Ty had 19 $20-notes. Ace only had $20-notes.

1. Who had the least amount of money?
2. How much less did Rey have than Ty?
3. Ty used all his $5-notes to buy a wallet. He then had $280 less than Ace. How many $20-notes did Ace have?

(a)
The three boys had the same number of notes.
$20-notes have a higher denomination than $5-notes.

Since Rey had the least number of $20-notes, he had the least money.

(b)
Number of less $20-notes that Rey had than Ty
= 19 - 9
= 10

Difference in the value of $20-note and $5-note
= 20 - 5
= $15

Amount that Rey had less than Ty
= 10 x 15
= $150

(c)
Value of $20-notes that Ty had left
= 19 x 20
= $380

Total value that Ace had
= 380 + 280
= $660

Number of $20-notes that Ace had
= 660 ÷ 20
= 33

Answer(s): (a) Rey; (b) $150; (c) 33