Abe, Luc and Jim had the same number of notes. Abe and Luc had a mix of $10-notes and $5-notes. Luc had 2 $10-notes while Abe had 12 $10-notes. Jim only had $10-notes.

1. Who had the least amount of money?
2. How much less did Luc have than Abe?
3. Abe used all his $5-notes to buy a wallet. He then had $280 less than Jim. How many $10-notes did Jim have?

(a)
The three boys had the same number of notes.
$10-notes have a higher denomination than $5-notes.

Since Luc had the least number of $10-notes, he had the least money.

(b)
Number of less $10-notes that Luc had than Abe
= 12 - 2
= 10

Difference in the value of $10-note and $5-note
= 10 - 5
= $5

Amount that Luc had less than Abe
= 10 x 5
= $50

(c)
Value of $10-notes that Abe had left
= 12 x 10
= $120

Total value that Jim had
= 120 + 280
= $400

Number of $10-notes that Jim had
= 400 ÷ 10
= 40

Answer(s): (a) Luc; (b) $50; (c) 40