Nat, Tom and Ty had the same number of notes. Nat and Tom had a mix of $20-notes and $5-notes. Tom had 5 $20-notes while Nat had 11 $20-notes. Ty only had $20-notes.

1. Who had the least amount of money?
2. How much less did Tom have than Nat?
3. Nat used all his $5-notes to buy a wallet. He then had $520 less than Ty. How many $20-notes did Ty have?

(a)
The three boys had the same number of notes.
$20-notes have a higher denomination than $5-notes.

Since Tom had the least number of $20-notes, he had the least money.

(b)
Number of less $20-notes that Tom had than Nat
= 11 - 5
= 6

Difference in the value of $20-note and $5-note
= 20 - 5
= $15

Amount that Tom had less than Nat
= 6 x 15
= $90

(c)
Value of $20-notes that Nat had left
= 11 x 20
= $220

Total value that Ty had
= 220 + 520
= $740

Number of $20-notes that Ty had
= 740 ÷ 20
= 37

Answer(s): (a) Tom; (b) $90; (c) 37