Abe, Ty and Lee had the same number of notes. Abe and Ty had a mix of $10-notes and $5-notes. Ty had 8 $10-notes while Abe had 16 $10-notes. Lee only had $10-notes.

1. Who had the least amount of money?
2. How much less did Ty have than Abe?
3. Abe used all his $5-notes to buy a wallet. He then had $160 less than Lee. How many $10-notes did Lee have?

(a)
The three boys had the same number of notes.
$10-notes have a higher denomination than $5-notes.

Since Ty had the least number of $10-notes, he had the least money.

(b)
Number of less $10-notes that Ty had than Abe
= 16 - 8
= 8

Difference in the value of $10-note and $5-note
= 10 - 5
= $5

Amount that Ty had less than Abe
= 8 x 5
= $40

(c)
Value of $10-notes that Abe had left
= 16 x 10
= $160

Total value that Lee had
= 160 + 160
= $320

Number of $10-notes that Lee had
= 320 ÷ 10
= 32

Answer(s): (a) Ty; (b) $40; (c) 32