Ian, Ben and Lee had the same number of notes. Ian and Ben had a mix of $50-notes and $5-notes. Ian had 2 $50-notes while Ben had 12 $50-notes. Lee only had $50-notes.
- Who had the least amount of money?
- How much more did Ben have than Ian?
- Ben used all his $5-notes to buy a wallet. He then had $950 less than Lee. How many $50-notes did Lee have?
(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $5-notes.
Since Ian had the least number of $50-notes, he had the least money.
(b)
Number of more $50-notes that Ben had than Ian
= 12 - 2
= 10
Difference in the value of $50-note and $5-note
= 50 - 5
= $45
Amount that Ben had more than Ian
= 10 x 45
= $450
(c)
Value of $50-notes that Ben had left
= 12 x 50
= $600
Total value that Lee had
= 600 + 950
= $1550
Number of $50-notes that Lee had
= 1550 ÷ 50
= 31
Answer(s): (a) Ian; (b) $450; (c) 31
