Asa, Lee and Luc had the same number of notes. Asa and Lee had a mix of $100-notes and $50-notes. Asa had 5 $100-notes while Lee had 14 $100-notes. Luc only had $100-notes.

1. Who had the least amount of money?
2. How much more did Lee have than Asa?
3. Lee used all his $50-notes to buy a wallet. He then had $3200 less than Luc. How many $100-notes did Luc have?

(a)
The three boys had the same number of notes.
$100-notes have a higher denomination than $50-notes.

Since Asa had the least number of $100-notes, he had the least money.

(b)
Number of more $100-notes that Lee had than Asa
= 14 - 5
= 9

Difference in the value of $100-note and $50-note
= 100 - 50
= $50

Amount that Lee had more than Asa
= 9 x 50
= $450

(c)
Value of $100-notes that Lee had left
= 14 x 100
= $1400

Total value that Luc had
= 1400 + 3200
= $4600

Number of $100-notes that Luc had
= 4600 ÷ 100
= 46

Answer(s): (a) Asa; (b) $450; (c) 46