Sam, Roy and Rio had the same number of notes. Sam and Roy had a mix of $10-notes and $5-notes. Sam had 17 $10-notes while Roy had 20 $10-notes. Rio only had $10-notes.

1. Who had the least amount of money?
2. How much more did Roy have than Sam?
3. Roy used all his $5-notes to buy a wallet. He then had $110 less than Rio. How many $10-notes did Rio have?

(a)
The three boys had the same number of notes.
$10-notes have a higher denomination than $5-notes.

Since Sam had the least number of $10-notes, he had the least money.

(b)
Number of more $10-notes that Roy had than Sam
= 20 - 17
= 3

Difference in the value of $10-note and $5-note
= 10 - 5
= $5

Amount that Roy had more than Sam
= 3 x 5
= $15

(c)
Value of $10-notes that Roy had left
= 20 x 10
= $200

Total value that Rio had
= 200 + 110
= $310

Number of $10-notes that Rio had
= 310 ÷ 10
= 31

Answer(s): (a) Sam; (b) $15; (c) 31