Ari, Jed and Ben had the same number of notes. Ari and Jed had a mix of $20-notes and $10-notes. Ari had 11 $20-notes while Jed had 15 $20-notes. Ben only had $20-notes.

1. Who had the least amount of money?
2. How much more did Jed have than Ari?
3. Jed used all his $10-notes to buy a wallet. He then had $500 less than Ben. How many $20-notes did Ben have?

(a)
The three boys had the same number of notes.
$20-notes have a higher denomination than $10-notes.

Since Ari had the least number of $20-notes, he had the least money.

(b)
Number of more $20-notes that Jed had than Ari
= 15 - 11
= 4

Difference in the value of $20-note and $10-note
= 20 - 10
= $10

Amount that Jed had more than Ari
= 4 x 10
= $40

(c)
Value of $20-notes that Jed had left
= 15 x 20
= $300

Total value that Ben had
= 300 + 500
= $800

Number of $20-notes that Ben had
= 800 ÷ 20
= 40

Answer(s): (a) Ari; (b) $40; (c) 40