Joe, Ari and Ken had the same number of notes. Joe and Ari had a mix of $10-notes and $5-notes. Joe had 3 $10-notes while Ari had 10 $10-notes. Ken only had $10-notes.
- Who had the least amount of money?
- How much more did Ari have than Joe?
- Ari used all his $5-notes to buy a wallet. He then had $350 less than Ken. How many $10-notes did Ken have?
(a)
The three boys had the same number of notes.
$10-notes have a higher denomination than $5-notes.
Since Joe had the least number of $10-notes, he had the least money.
(b)
Number of more $10-notes that Ari had than Joe
= 10 - 3
= 7
Difference in the value of $10-note and $5-note
= 10 - 5
= $5
Amount that Ari had more than Joe
= 7 x 5
= $35
(c)
Value of $10-notes that Ari had left
= 10 x 10
= $100
Total value that Ken had
= 100 + 350
= $450
Number of $10-notes that Ken had
= 450 ÷ 10
= 45
Answer(s): (a) Joe; (b) $35; (c) 45
