Jed, Ray and Ben had the same number of notes. Jed and Ray had a mix of $50-notes and $20-notes. Jed had 8 $50-notes while Ray had 15 $50-notes. Ben only had $50-notes.
- Who had the least amount of money?
- How much more did Ray have than Jed?
- Ray used all his $20-notes to buy a wallet. He then had $1550 less than Ben. How many $50-notes did Ben have?
(a)
The three boys had the same number of notes.
$50-notes have a higher denomination than $20-notes.
Since Jed had the least number of $50-notes, he had the least money.
(b)
Number of more $50-notes that Ray had than Jed
= 15 - 8
= 7
Difference in the value of $50-note and $20-note
= 50 - 20
= $30
Amount that Ray had more than Jed
= 7 x 30
= $210
(c)
Value of $50-notes that Ray had left
= 15 x 50
= $750
Total value that Ben had
= 750 + 1550
= $2300
Number of $50-notes that Ben had
= 2300 ÷ 50
= 46
Answer(s): (a) Jed; (b) $210; (c) 46