At a bowling alley, an adult ticket cost $10 and a child ticket cost $1. Last Thursday, the bowling alley sold 89 more adult tickets than child tickets. A total of $1297 was collected. How many child tickets were sold?
|
Adults |
Children |
Total |
Number |
1 u + 89 |
1 u |
2 u |
Value |
$10 |
$1 |
|
Total value |
10 u + 890 |
1 u |
11 u + 890 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $10
Number of children = 1 u
Number of adults = 1 u + 89
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 10(1 u + 89) = 10 u + 890
Total cost of all the tickets
= 1 u + 10 u + 890
= 11 u + 890
11 u + 890 = 1297
11 u = 1297 - 890
11 u = 407
1 u = 407 ÷ 11 = 37
Number of child tickets = 37
Answer(s): 37