At a bowling alley, an adult ticket cost $4 and a child ticket cost $1. Last Tuesday, the bowling alley sold 92 more adult tickets than child tickets. A total of $608 was collected. How many child tickets were sold?
| |
Adults |
Children |
Total |
| Number |
1 u + 92 |
1 u |
2 u |
| Value |
$4 |
$1 |
|
| Total value |
4 u + 368 |
1 u |
5 u + 368 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $4
Number of children = 1 u
Number of adults = 1 u + 92
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 4(1 u + 92) = 4 u + 368
Total cost of all the tickets
= 1 u + 4 u + 368
= 5 u + 368
5 u + 368 = 608
5 u = 608 - 368
5 u = 240
1 u = 240 ÷ 5 = 48
Number of child tickets = 48
Answer(s): 48
