At a bowling alley, an adult ticket cost $8 and a child ticket cost $1. Last Saturday, the bowling alley sold 53 more adult tickets than child tickets. A total of $811 was collected. How many child tickets were sold?
|
Adults |
Children |
Total |
Number |
1 u + 53 |
1 u |
2 u |
Value |
$8 |
$1 |
|
Total value |
8 u + 424 |
1 u |
9 u + 424 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $8
Number of children = 1 u
Number of adults = 1 u + 53
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 8(1 u + 53) = 8 u + 424
Total cost of all the tickets
= 1 u + 8 u + 424
= 9 u + 424
9 u + 424 = 811
9 u = 811 - 424
9 u = 387
1 u = 387 ÷ 9 = 43
Number of child tickets = 43
Answer(s): 43