At a bowling alley, an adult ticket cost $2 and a child ticket cost $1. Last Saturday, the bowling alley sold 68 more adult tickets than child tickets. A total of $217 was collected. How many child tickets were sold?
| |
Adults |
Children |
Total |
| Number |
1 u + 68 |
1 u |
2 u |
| Value |
$2 |
$1 |
|
| Total value |
2 u + 136 |
1 u |
3 u + 136 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $2
Number of children = 1 u
Number of adults = 1 u + 68
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 2(1 u + 68) = 2 u + 136
Total cost of all the tickets
= 1 u + 2 u + 136
= 3 u + 136
3 u + 136 = 217
3 u = 217 - 136
3 u = 81
1 u = 81 ÷ 3 = 27
Number of child tickets = 27
Answer(s): 27
