At a bowling alley, an adult ticket cost $7 and a child ticket cost $1. Last Sunday, the bowling alley sold 82 more adult tickets than child tickets. A total of $966 was collected. How many child tickets were sold?
| |
Adults |
Children |
Total |
| Number |
1 u + 82 |
1 u |
2 u |
| Value |
$7 |
$1 |
|
| Total value |
7 u + 574 |
1 u |
8 u + 574 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $7
Number of children = 1 u
Number of adults = 1 u + 82
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 7(1 u + 82) = 7 u + 574
Total cost of all the tickets
= 1 u + 7 u + 574
= 8 u + 574
8 u + 574 = 966
8 u = 966 - 574
8 u = 392
1 u = 392 ÷ 8 = 49
Number of child tickets = 49
Answer(s): 49
