At a bowling alley, an adult ticket cost $5 and a child ticket cost $1. Last Monday, the bowling alley sold 99 more adult tickets than child tickets. A total of $645 was collected. How many child tickets were sold?
| |
Adults |
Children |
Total |
| Number |
1 u + 99 |
1 u |
2 u |
| Value |
$5 |
$1 |
|
| Total value |
5 u + 495 |
1 u |
6 u + 495 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $5
Number of children = 1 u
Number of adults = 1 u + 99
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 5(1 u + 99) = 5 u + 495
Total cost of all the tickets
= 1 u + 5 u + 495
= 6 u + 495
6 u + 495 = 645
6 u = 645 - 495
6 u = 150
1 u = 150 ÷ 6 = 25
Number of child tickets = 25
Answer(s): 25
