At a bowling alley, an adult ticket cost $6 and a child ticket cost $1. Last Saturday, the bowling alley sold 90 more adult tickets than child tickets. A total of $876 was collected. How many child tickets were sold?
| |
Adults |
Children |
Total |
| Number |
1 u + 90 |
1 u |
2 u |
| Value |
$6 |
$1 |
|
| Total value |
6 u + 540 |
1 u |
7 u + 540 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $6
Number of children = 1 u
Number of adults = 1 u + 90
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 6(1 u + 90) = 6 u + 540
Total cost of all the tickets
= 1 u + 6 u + 540
= 7 u + 540
7 u + 540 = 876
7 u = 876 - 540
7 u = 336
1 u = 336 ÷ 7 = 48
Number of child tickets = 48
Answer(s): 48
