At a bowling alley, an adult ticket cost $4 and a child ticket cost $1. Last Sunday, the bowling alley sold 65 more adult tickets than child tickets. A total of $435 was collected. How many child tickets were sold?
| |
Adults |
Children |
Total |
| Number |
1 u + 65 |
1 u |
2 u |
| Value |
$4 |
$1 |
|
| Total value |
4 u + 260 |
1 u |
5 u + 260 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $4
Number of children = 1 u
Number of adults = 1 u + 65
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 4(1 u + 65) = 4 u + 260
Total cost of all the tickets
= 1 u + 4 u + 260
= 5 u + 260
5 u + 260 = 435
5 u = 435 - 260
5 u = 175
1 u = 175 ÷ 5 = 35
Number of child tickets = 35
Answer(s): 35
