At a bowling alley, an adult ticket cost $5 and a child ticket cost $1. Last Saturday, the bowling alley sold 73 more adult tickets than child tickets. A total of $665 was collected. How many child tickets were sold?
|
Adults |
Children |
Total |
Number |
1 u + 73 |
1 u |
2 u |
Value |
$5 |
$1 |
|
Total value |
5 u + 365 |
1 u |
6 u + 365 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $5
Number of children = 1 u
Number of adults = 1 u + 73
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 5(1 u + 73) = 5 u + 365
Total cost of all the tickets
= 1 u + 5 u + 365
= 6 u + 365
6 u + 365 = 665
6 u = 665 - 365
6 u = 300
1 u = 300 ÷ 6 = 50
Number of child tickets = 50
Answer(s): 50