At a bowling alley, an adult ticket cost $6 and a child ticket cost $1. Last Saturday, the bowling alley sold 50 more adult tickets than child tickets. A total of $468 was collected. How many child tickets were sold?
|
Adults |
Children |
Total |
Number |
1 u + 50 |
1 u |
2 u |
Value |
$6 |
$1 |
|
Total value |
6 u + 300 |
1 u |
7 u + 300 |
Cost of 1 child ticket = $1
Cost of 1 adult ticket = $6
Number of children = 1 u
Number of adults = 1 u + 50
Total cost of child tickets = 1 u x 1 = 1 u
Total cost of adult tickets = 6(1 u + 50) = 6 u + 300
Total cost of all the tickets
= 1 u + 6 u + 300
= 7 u + 300
7 u + 300 = 468
7 u = 468 - 300
7 u = 168
1 u = 168 ÷ 7 = 24
Number of child tickets = 24
Answer(s): 24