Marion had 13 more sweets than Peter at first. After Peter had eaten 17 of his sweets, Marion had 4 times as many sweets as Peter. How many sweets did Marion and Peter have in total at first?
| |
Marion |
Peter |
Total |
| Before |
1 u + 17 + 13 |
1 u + 17 |
5 u + 17 |
| Change |
|
- 17 |
|
| After |
4 u |
1 u |
|
The number of sweets that Marion had at first remains unchanged.
4 u = 1 u + 17 + 13
4 u - 1 u = 30
3 u = 30
1 u = 30 ÷ 3 = 10
Number of sweets that they had at first
= 5 u + 17
= 5 x 10 + 17
= 50 + 17
= 67
Answer(s): 67
