Raeann had 12 more sweets than Andy at first. After Andy had eaten 12 of his sweets, Raeann had 3 times as many sweets as Andy. How many sweets did Raeann and Andy have in total at first?
| |
Raeann |
Andy |
Total |
| Before |
1 u + 12 + 12 |
1 u + 12 |
4 u + 12 |
| Change |
|
- 12 |
|
| After |
3 u |
1 u |
|
The number of sweets that Raeann had at first remains unchanged.
3 u = 1 u + 12 + 12
3 u - 1 u = 24
2 u = 24
1 u = 24 ÷ 2 = 12
Number of sweets that they had at first
= 4 u + 12
= 4 x 12 + 12
= 48 + 12
= 60
Answer(s): 60
